[quote=@Kho] Now, if we are to divide the past participle of the future participle of Turn Six to the power of ninety-five point two three recurring, then proceed to add it to the present perfect participle of Turn 28, you will have arrived at a positive integer that is equal to the sum of its proper positive divisors, that is, the sum of its positive divisors excluding the number itself. [/quote] And, of course, by doing so, we can extract the determinant of the Gaussian tensor of Might Points, which enables us to superimpose stochastic perturbations upon the antiderivative. If we then apply that with the Hamiltonian to a commutator, we can negate that from the quotient of Turn Two. Finally, we normalise the second partial derivative of Turn Seven to unity, such that the weighted quartic splines will predict Logos' Might this turn to within numerical precision. [colour=2E2C2C]Did you seriously try to do arithmetic upon word components, Kho? Come on, if you're going to technobabble, at least do it properly.[/colour]