[quote=@Legend]
<Snipped quote by Multifarious>

Not sure why anyone wouldn't use the built in x^5, but you could do something like


public int powerUp(int num, int power)
{
	if(power == 0)			//Stop condition
		return 1;
	else if (power > 1)		//Positive powers
		return powerUp(num, power - 1) * num;
	else				//Negative powers
		return 1 / powerUp(num, power + 1) * num;
}
[/quote]

Oh, one over the power makes so much sense. Duh. Kill me now.