So, hrm, he got [url=https://www.roleplayerguild.com/rolls/14329] 1 and 4.[/url] This door is his new archnemesis omg. 

Though rereading the part on multiple dice made me wonder... If a success is a roll of 4 or more, but it's not enough that one roll of many passes that threshold, doesn't having multiple dice make it even more difficult to succeed? Since it's more difficult to get a number above 3 two times in a row than only once. Getting above 3 once is a 50% chance, but doing it twice in a row is 25%. There is a chance that two of the numbers are the same, which gives you that bonus you mentioned, but it's still easier to get above 3 on a singular roll. 

Then again, since 3 is a near success, if you got 3 and 4 and that counted as a success, it would bump the odds up a bit. Getting above 2 twice in a row would be a 44% chance (66% on a singular die). Closer to the 50%, but not quite. And that would get even more difficult the more die we add. Though, if we add more die, the chance of doubles also raises. Double 1's don't count, but since double 2 and 3 do, that helps with the odds. I'm not sure whether that totals up to better chance of success than the original 50% of one die though. If it does... Is it just 2 dice specifically that faces this problem? 

Admittedly I might have misunderstood something. Also, I do have rotten luck, ha, and  I'm also not trying to wiggle out of a bad roll or anything! Bad rolls are usually where the fun happens. Just it made me curious as to how the odds worked. For example, if I'd only had 1 die to roll in this instance, and I would've gotten the 2 that I rolled at first, aka failed - - then I could've tried again, and gotten the 5 I rolled right after, would that have been a success? Technically, wouldn't Pebs have a better chance at the door, since she only has to roll above 3 once?

Or am I totally off base? Either way, err, sorry for the long explanation, just trying to wrack my own brain as I go since I'm not an expert on probability, heh.