I usually don't look in the Tabletop section, I certainly didn't expect to see RISUS! Any chance you'd still consider running a game?
@Clever Hans I have never played, or heard of the Flashing Blades RPG. I am however an avid fan if history, having read a multitude of tomes and articles on the subject since I was ten years old. I love historical Roleplays and could be interested in this one. Is this kind of like a Spanish version of the Three Musketeers? I see this has the backdrop of not only King Phillip II's death, but also the 30 years' War mostly fought in the Germanic States with Spain on the side of the Hapsburgs of Austria.
I see. Well, unfortunately, something come up, so I'm going to have to opt out.
Hm, this could be interesting. Is this going to be a historical rp? I have a couple characters I could use for this sort of thing.
I thought that title's one of those ad bots lol.
Run it in 7th Sea
@Clever Hans You'd better not be trying to get me to do your math homework.
<lots of amazingness edited out>
I have a (43.75% + 56.25%) ÷ 2 = 50.00% chance to win.
You have a (43.75% + 31.25%) ÷ 2 = 37.50% chance to win.
And we have a 12.5% chance to tie.
<Snipped quote by Mae>
The chance of landing on any side of an 8-sided dice is 12.5%. Therefor, you have a 25% chance of rolling something that is unattainable on a 6-sided dice, and a 37.5% chance to at least get something equal to the highest number on a 6. Compare that to a 0% or 16%-ish chance respectively. Or if you prefer a non % based representation of this in the real world, let's do number of times out of 24 since that's a number both 6 and 8 go into. If you rolled both dice 24 times, the d6 would give you a 6 only 4 times, where the d8 would give you a 6 or greater an astounding 9 times.
Another fun test, let's pretend you have "perfectly normal" luck and you'll always roll each side of the dice the same number of times. in 24 rolls, You'd roll every side of the d6 4 times which is (1 + 2 + 3 + 4 + 5 + 6) X 4 = 84. Meanwhile, with the 8 you would get each side 3 times for a total of (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8) X 3 = 108